High-speed stroboscopic photographs show that the head of a 214 g golf club is trav- eling at 36.7 m/s just before it strikes a 45.9 g golf ball at rest on a tee. after the collision, the club head travels (in the same direction) at 26.9 m/s. find the speed of the golf ball immediately after impact. answer in units of m/s.

v = 45.7 m/s

Explanation:

It is given that the head of a golf club has a mass of 214 g and is travelling at 36.7 m.s before the impact with a golf ball which has a mass of 45.9 g and is at rest on a tee.

After the club hits the ball, its speed decreases to 26.9 m/s and we are to determine the speed of the golf ball after the impact.

So, the initial momentum () = 36.7 * 214 = 7853.8 g; and

the final momentum () = 45.9 * v + 214 * 26.9

Since () = (),

7853.8 = 45.9v + 5756.6

45.9v = 2097.2

v = 45.7 m/s

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!

pecialized keyboards