An object with mass m is attached to the end of a string and is raised vertically at a constant acceleration of g 10 . if it has been raised a distance ℓ from rest, how much work has been done by the tension in the string?

The work by tension is ¹¹/₁₀ Mgℓ

Complete Question:

An object with mass M is attached to the end of a string and is raised vertically at a constant acceleration of g/10 . If it has been raised a distance ℓ from rest, how much work has been done by the tension in the string?

Given:

Mass of the object = M

Acceleration of the object = g/10

Distance = ℓ

Asked:

Work by Tension = W = ?

Solution:

Let's find the magnitude of tension as follows:

The work by tension is ¹¹/₁₀ Mgℓ

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

3.2x10^7