Soluonscheg phy 1848/2348 summer 2019 messages courses logout main menu contents grades reservations course contents hw #6 (07/04 th 11: 59 pm) magnetic flux of a solenold timer notes valuate eedhack print a solenoid 6.76 cm in diameter and 19.0 cm long has 263 turns and carries a current of 14.6 a. calculate the magnetic flux through the circular cross-sectional area of the solenoid. submit anwe tries 0/12 threaded view chronological view other views. export my general preferences on what is marked as new mark new posts no longer new new units anonymous 1 reply (wed jul 3 06: 12: 33 pm 2019 (edt)) what units do we use for this question?

It equals just about 6,300 km per hour each day an week

Answertraveling around a circular trackexplanation"traveling around a circular track" is the best answer as you could be traveling around a circular track at a constant speed. your velocity would therefore have the same magnitude but will always be constantly direction. since acceleration is the rate of change of velocity, the rate of change will only involve the direction of velocity and not the magnitude.wrong choices: "an object at rest" does not accelerate at all"increasing speed while traveling around a curve" means that the acceleration will not be constant due to only change in direction; it will be constant due to both magnitude and direction"an object in free fall" does not necessarily change direction 

490 n  f=125n a=2.5m/s2