A30.0-kg girl in a swing is pushed to one side and held at rest by a horizontal force →f so that the swing ropes are 30.0° with respect to the vertical. (a) calculate the tension in each of the two ropes supporting the swing under these conditions. (b) calculate the magnitude of →f .

The tension in each of the two ropes supporting the girl, swing under these condition is 170 N and the magnitude of is 170 N.

Tension is the pulling force carried by the flexible mediums like ropes, cables, and string. Tension in a body due to the weight of the suspension body is the net force acting on the body.

For the body with mass (m) hanging on a string, the tension force of the string for the component of weight in the direction of sting, can be given as,

Here, (g) is the gravitational force.

The weight of the girl is 30.0-kg. The girl held at rest by a horizontal force, so that the swing ropes are 30.0° with respect to the vertical. Thus, put the values in the above formula as,

Thus, the tension in each of the two ropes supporting the swing under these conditions is 170 N.

The tension force of the string, for the component of weight perpendicular to the sting, can be given as,

In the terms of Force,

Put the values,

Thus, the magnitude of is 170 N.

The tension in each of the two ropes supporting the girl, swing under these condition is 170 N and the magnitude of is 170 N.

Learn more about the tension in the string here;

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Part a)

Part b)

F = 170 N

Explanation:

As we know that swing is at rest in this situation

so here all the forces on the swing must be balanced

so here we have

so here we have

Now in the horizontal direction force is also balanced

so we have

now we have

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures