Aproton, which moves perpendicular to a magnetic field of 1.35 t in a circular path of radius 0.072 m, has what speed? (qp = 1.6 · 10 19 c and mp = 1.67 · 10 27 kg)

Speed of the proton is

Explanation:

It is given that,

Magnetic field, B = 1.35 T

Radius of circular path, r = 0.072 m

The centripetal force is balanced by the magnetic force such that,

q and m is the charge and mass of a proton respectively

So, the speed if the proton is . Hence, this is the required solution.

explanation:

wheres the pic