A20-μf capacitor has a charge of 60 μc. how much energy is stored in this capacitor? a) 100 μj b) 80 μj c) 90 μj d) 70 μj e) 110 μj

C...90

Explanation:

Energy stored = 1/2 of(Charge × Voltage)

then substitute Voltage with (Charge ÷ Capacitance)

Then obtain the formula for energy stored as

E = 1/2 of (Charge)^2 ÷ Capacitance

= 0.5 x (60^2÷20)

;Energy stored = 90

because growing process had stoped after 4-5 year

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explanation: