The electron gun in a television tube accelerates electrons (mass = 9.11x10^-31 kg, charge = 1.6 x 10^-19c) from rest to 3 x10^7 m/s within a distance o 2 cm. what electric field is required?

Electric field acting on the electron is  127500 N/C.

Explanation:

It is given that,

Mass of an electron,

Charge on electron,

Initial speed of electron, u = 0

Final speed of electron,

Distance covered, s = 2 cm = 0.02 m

We need to find the electric field required. Firstly, we will find the acceleration of the electron from third equation of motion as :

According to Newton's law, force acting on the electron is given by :

F = ma

Electric force is given by :

F = q E, E = electric field

E = 127500 N/C

So, the electric field is 127500 N/C. Hence, this is the required solution.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards