10 pts a cube of water ice (rho = 0.917 × 103 kg/m3) is placed in mercury (rho = 13.6 × 103 kg/m3), which is liquid at 0° celsius. if we ignore any possible melting of the ice cube and problems with the surface tension of mercury, the fraction of the ice cube that floats above the surface of the mercury is

fraction of ice cube float is 0.933

Explanation:

given data

density of ice = 0.917  × 10³ kg/m³

density of mercury = 13.6  × 10³ kg/m³

to find out

what is fraction of the ice cube floats

solution

we find first ice submerged volume that is

ice submerged volume =  

put here value

ice submerged volume =  

ice submerged volume = 0.0674

so here fraction of ice cube float is

fraction = 1 - 0.0674

fraction = 0.933

so fraction of ice cube float is 0.933

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

where’s the list ? the question is incomplete