Abaseball is thrown directly upward from ground level with a velocity of +15 m/s. what are the two times when the ball is 10 m above ground level? take acceleration due to gravity to be –9.8 m/s^2 .

time is 0.5660 s

and time is - 3.62431  s

Explanation:

velocity u = 15 m/s

height s = 10 m

acceleration due to gravity g =  –9.8 m/s²

to find out

time

solution

we will apply here distance equation that is

s = ut - 1/2× gt²   1

here put all these value and get time t

here s is height and g is -9.8

so

s = ut - 1/2× gt²

10 = 15t - 1/2× (-9.8)t²

10 = 15t + 4.9t²

solve it we get t

t = 0.56630 and -3.62431

so time is 0.5660 s

and time is - 3.62431  s

its c its is a mixture of gases