Acar travels in the +x-direction on a straight and level road. for the first 3.00 s of its motion, the average velocity of the car is υav−x = 6.31 m/s .
how far does the car travel in 4.00s?

25.24 m

Explanation:

We are given that a car travels in the positive x direction on  a straight and level road.

We have to find the distance travel by car in 4 s.

Average velocity of car=6.31 m/s

Time =3 s

Distance traveled by the car in 3 sec=

Distance traveled by the  car  in 3 sec=

Distance traveled by the car in 1 sec=6.93 m

Distance traveled by the car in 4 sec=

Hence,distance traveled by the car in 4 sec=25.24 m

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .