Arace car travels 40 m/s around a banked (45° with the horizontal) circular (radius = 0.20 km) track. what is the magnitude of the resultant force on the 80-kg driver of this car? o a. 0.72 kn o b.0.68 kn o c. 0.64 kn o d.0.76 kn o e. 0.52 kn

c)

Explanation:

As we know that resultant force is the net force that is acting on the system

As per Newton's II law we know that net force is product of mass and acceleration

so we will have

here we know

m = 80 kg

for circular motion acceleration is given as

now we have

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

this would be about 43%