An electrostatic paint sprayer has a potential of 25.0 kv that repels paint droplets onto a grounded object. what charge must a 0.63 mg drop of paint have to arrive at the object with a speed of 9 m/s? give answer in terms of 10^-10 c.

10⁻⁶ C

Explanation:

Let the charge be Q

Gain of energy in electric field

= potential x charge

= 25 x 10³ x Q

Kinetic energy of droplet

= .5 x .63 x 10⁻³ x 9 x 9

= 25.515 x 10⁻³ J

So , equating the energy gained

25 x 10³ x Q = 25.515 x 10⁻³

Q = 10⁻⁶ C

the answer is b ) square root of 5