Two vectors, r with arrow and s with arrow, lie in the xy plane. their magnitudes are 4.40 and 7.45 units, respectively, and their directions are 310° and 84.5°, respectively, as measured counterclockwise from the positive x axis. what are the values of the following products?

The result is a vector perpendicular to the xy plane: 23.38 k

Explanation:

The cross product of two vectors r and s is defined only in three-dimensional space and is denoted by r × s. The cross product is defined by the formula:

r × s =║r║·║s║· Sin θ· n

where θ is the angle between r and s in the plane containing them, ‖r‖ and ‖s‖ are the magnitudes of vectors r and s, and n is a unit vector perpendicular to the plane containing a and b in the direction given by the right-hand rule.

So, the result is:

r × s = 4.40 * 7.45 * Sin (134.5°) k = 23.38 k

double the distance = divide strength by 4