Astudent determined to test the law of gravity for himself walks off a skyscraper 900 ft high, stopwatch in hand, and starts his free fall (zero initial velocity). five seconds later, superman arrives at the scene and dives off the roof to save the student. (a) what must superman’s initial velocity be in order that he catch the student just before the ground is reached? (b) what must be the height of the skyscraper so that even superman can’t save him? (assume that superman’s acceleration is that of any freely falling body.)

a) 323.517 ft/s

b) 402.5 ft

Explanation:

At t = 5s the student had travelled:

y = (32/2)*5^2 ft

y = 402.5 ft

The time at which the student will reach the ground is given by:

900 ft = (32/2 ft/s^2)* t^2

Solving for t

t = (1800/32 s^2)^(1/2)

t = 7.47667 s

Therefore Superman need to travell 900 ft in 2.47667 s

The equation of motion of Superman will be:

ys(t)=v0*t + (32.2/2 ft/s^2)*t^2

We are looking for a velocity v0 such that  ys(2.47667 s) = 900 ft:

900 ft = v0*(2.47667 s) + (32.2/2  * (2.47667)^2) ft

v0 = (900 - (32.2/2) (2.47667)^2)/  (2.47667)   ft/s

v0 = 323.517 ft/s

The hight of the skyscraper so that even Superman cant save him will be the same as the distance y0 the student has travelled when superman arrived, that is:

y(t) = - (32.2 (ft/s^2) /2)*(25s^2) = 402.5 ft

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.