Tanner jones and sheldon furst have received communications receivers for christmas. if they leave from the same point at the same time, tanner walking north at 3.0 mph and sheldon walking east at 3.5 mph, how long will they be able to talk to each other if the range of communications receivers is 8 miles? (round your answer to the nearest minute.)

t = 1.735 s

Explanation:

given,

tanner walking speed = 3 mph

Sheldon walking speed = 3.5 mph

distance = speed × time

tanner distance = 3 t

Sheldon distance = 3.5 t

Using Pythagoras theorem

(3.5 t)²+ (3 t)² = 8²

21.25 t² = 64

t = 1.735 s

tanner walks the distance of = 3 × 1.735 = 5.205 m

Sheldon walks the distance of = 3.5 × 1.735 = 6.072 m

so, the distance between them

 d² = 5.205² + 6.072²

d = 8 miles (hence correct)

for, 1.735 s they are able to talk to each other.

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000