Consider a cylinder with water filled to a height of 50 cm. at a height of 10 cm is a hole in the side of the cylinder . assuming that there is no viscous drag of the fluid flowing through the hole, what is the velocity of the fluid squirting out of it? (hint: you will need to use bernoulli, and make the assumption that the pressure of the water just as it leaves the hole, since it is in contact with the air, is just atmospheric pressure.)

Explanation:

The Bernoulli equation tells us that in a fluid , so we will apply this to a point on the surface and a point on the hole.

For a point on the surface (at height ) the velocity will be approximated to 0m/s since we assume it barely moves (unless other information is given), so we have:

For a point on the hole (at height and velocity of the fluid ) we have:

Since both constant are the same, cancelling we have:

Which means:

So the velocity of the fluid flowing through the hole will be:

no

sodium is solid at rt

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.