The speed of a car during a trip is represented in the graph. compare distance and displacement at four hours into the trip.
a) the distance traveled is 300 km.
b) distance is 300 km and displacement is 0 km.
c) distance is 300 km/hour and displacement is 300 km.
d) both distance traveled and displacement are 300 km.

The answer to your question is: D.

Explanation:

Distance refers to the amount of space between two points, it is a scalar quantity.

Displacement refers to the space between two points, measure from the minimum path linking them, it is a vector quantity.

I'm not agree with these answers, because the total distance  is approximately 500km.

A) The distance traveled is 300 km.  This answer is not correct.

B) Distance is 300 km and displacement is 0 km.  This answer is not correct because the displacement is also 500 km.

C) Distance is 300 km/hour and displacement is 300 km. 300 km/h is a measure of speed not of distance, this option is wrong.

D) Both distance traveled and displacement are 300 km. I think this is the correct answer because distance and displacement measure the same. but I think both measure 500 km.

A) The distance traveled is 300 km.

Explanation:

Since the graph represents the distance time graph so we don't have any idea about the path length of the car.

So here we can not comment about the displacement of the motion of the car

so here we can see from the graph that

at t = 0  the position of the car is x = 0

now when car will reach at t = 4 hour

the distance of the car is

d = 300 km

so we can say that distance covered by the car will be

d = 300 km

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation