Determine the time it takes for a satellite to orbit the earth in a circular "near-earth" orbit. a "near-earth" orbit is at a height above the surface of the earth that is very small compared to the radius of the earth. [hint: you may take the acceleration due to gravity as essentially the same as that on the surface.]

Explanation:

The gravitational force a satellite of mass m orbiting the Earth of mass at a radius equal to the radius of the Earth is:

Where is the gravitational constant.

Newton's 2nd Law tells us that this satellite of mass m under the mentioned force F will experiment an acceleration given by F=ma.

This acceleration is a centripetal acceleration, so we can use the formula:

The velocity will be given by the relation between the circumference of the orbit and the time taken, that is, v=C/t, and we know that the circumference is .

We can put everything together now:

Substituting our values we have:

Which are more than 84 minutes. For reference, the ISS has a period of almost 93 minutes, so we know the result makes sense (and the equation will give us this result considering it orbits 408Km above Earth's surface).

volts times amps 6 x 0.5 3w

i think it would be 5