Physics, 17.10.2019 07:10 ksiandua07

Ahorse and rider are racing to the right with a speed of 21\,\dfrac{\text m}{\text s}21 s m 21, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when they pass the finish line and begin slowing down. the horse slows for 52\,\text m52m52, start text, m, end text with constant acceleration before it stops. what was the acceleration of the horse as it came to a stop? answer using a coordinate system where rightward is positive. round the answer to two significant digits.

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Answer from: solo4360

a=-4.2 m/s²

Explanation:

The horse riding so inital velocity is given finally the rider stops so the final velocity is zero.

initial velocity =Vi= 21 m/s

final velocity =Vf= 0 m/s

distance covered = S=52 m

By using 2nd equation of motion we can find the acceleration

2aS=Vf² -Vi²

a=(-441)/104

a=-4.2 m/s²

So the accceleration is 4.2 m/s².

Answer from: Joshghopper

The acceleration of the horse as it came to a stop is $4.24\ m/s^2$ .

Explanation:

Given that,

Initial speed of the horse and rider, u = 21 m/s

It finally comes to rest, v = 0

The horse slows down for 52 m with constant acceleration before it stops.

We need to find the acceleration of the horse as it came to a stop. Let a is the acceleration. We can find it using third equation of motion as :

$v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{-u^2}{2d}\\\\a=\dfrac{-(21)^2}{2\times 52}\\\\a=-4.24\ m/s^2$

So, the acceleration of the horse as it came to a stop is $4.24\ m/s^2$ . Negative sign shows deceleration.

Answer from: Quest

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

Answer from: Quest

distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

slope of a graph = change in value of y -axis / change in values of x -axis

comparing both the equations

change in value of y -axis = change in position

change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

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