One of the most studied objects in the night sky is the crab nebula, the remains of a supernova explosion observed by the chinese in 1054. in 1968 it was discovered that a pulsar-a rapidly rotating neutron star that emits a pulse of radio waves with each revolution-lies near the center of the crab nebula. the period of this pulsar is 33 ms. what is the angular speed in rad/s of the crab nebula pulsar?

The angular speed of the Crab nebula pulsar is 190.3 rad/s.

Explanation:

Given that,

Time T= 33 ms = 0.033 s

The angular speed is equal to the 2π divided by time period.

We need to calculate the angular speed of the Crab nebula pulsar

Using formula of angular speed

Where, T = time

= angular speed

Put the value into the formula

Hence, The angular speed of the Crab nebula pulsar is 190.3 rad/s.

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