Abichromatic source produces light having wavelengths in vacuum of 450 nm and 650 nm. the indices of refraction are 1.440 and 1.420, respectively. in the situation above, a ray of the bichromatic light, in air, is incident upon the oil at an angle of incidence of 50.0°. the angle of dispersion between the two refracted rays in the oil is closest to:

The angle of dispersion between the two refracted rays in the oil is 0.51°.

Explanation:

Given that,

Wavelength in vacuum

The indices of refraction is

We need to calculate the refracted angle for 450 wavelength

Using Snell's law

Put the value into the formula

We need to calculate the refracted angle for 650 wavelength

Using Snell's law

Put the value into the formula

We need to calculate the angle of dispersion between the two refracted rays in the oil is

Put the value into the formula

Hence, The angle of dispersion between the two refracted rays in the oil is 0.51°.

when heated, the valance electrons increased their speed and transferred the heat from electron to electron.   i just took the test.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2