An average person can reach a maximum height of about 60 {\rm cm} when jumping straight upfrom a crouched position. during the jump itself, the person's bodyfrom the knees up typically rises a distance of around 50 {\rm cm}. to keep the calculationssimple and yet get a reasonable result, assume that the entirebody rises this much during the jump. in terms of this jumper's weight w , what force does the ground exert on him or herduring the jump?

2.2 W where W is the weight of the jumper.

Explanation:

A) use the formula

V^2 = 2gh= 2*9.81*60

that gives

V = 3.43 m/s

b) W = mg

during the jump , the displacement of the body is d =0.5m

so the acceleration a = (V^2-Vo^2)/2d = 11.76 m/s^2

net force applied by ground = m(g+a) = W/g(g+a)

= 2.2 W

electric field is a function of 1/r^2

yes, the force per unit charge for a point charge is inverse square law.

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//