To understand the origin of the torque on a current loop due to the magnetic forces on the current-carrying wires.

this problem will show you how to calculate the torque on a magnetic dipole in a uniform magnetic field. we start with a rectangular current loop, the shape of which allows us to calculate the lorentz forces explicitly. then we generalize our result. even if you already know the general formula to solve this problem, you might find it instructive to discover where it comes from.

a) give a more general expression for the magnitude of the torque τ. rewrite the answer found in part a in terms of the magnitude of the magnetic dipole moment of the current loop m. define the angle between the vector perpendicular to the plane of the coil and the magnetic field to be ϕ, noting that this angle is the complement of angle θ in part a.

give your answer in terms of the magnetic moment m, magnetic field b, and ϕ.

i think its

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.

at right angles to each other