A5.5kg block is hanging from a rope that is wrapped around the outside of a 13kg flywheel disk witha radius of 33cm that is hagning form the ceilin. friction in the flywheel provides a constant torque of 2.5nm. when the block is released what is the magnitude of its acceleration as it falls

Explanation:

Using second law of motion

where m1 is mass of block, m2 is mass of flywheel, g is acceleration due to gravity whose value is taken as , T is torque and r is radius

Substituting 5.5 Kg for m1, 13 Kg for m2, 0.33 m for r, 2.5 Nm for T we obtain

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