Vector v⃗ 1 points along the z axis and has magnitude v1 = 76. vector v⃗ 2 lies in the xz plane, has magnitude v2 = 60, and makes a -48 ∘ angle with the x axis (points below x axis).

what is the scalar product of the two vectors? express answer using two significant figures.

R= - 3388.74

Explanation:

Given that

V₁= 76 k  ( in z-direction)

θ = 48°

V₂ = 60 cos48° i - 60 sin48°  k

The dot product of two vector given as

We know that dot product of two vector  is scalar and cross product of two vector is vector.

R= V₁ . V₂

We have to remember

i.i= j.j = k.k = 1

i.j = j.k = k.i = 0

Now

R= V₁ . V₂

R= (76 k ).(  60 cos48° i - 60 sin48°  k)

R= 0 - 60 x 76  sin48°

R= - 3388.74

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