Aconductor of length 0.8 m carrying a current of 2.5 a is kept in a magnetic field of 0.6 tesla. what is the magnitude of the force experienced by the conductor if it is inclined at an angle 30° to the direction of the magnetic field?

0.6N

Explanation:

To calculate the magnitude of the force experienced by the conductor, we use the formulae

F= BILsintheta

Where B is the magnetic field

I is the current

L is the length

theta is the angle that the conductor made with the magnetic field

Substituting the given parameters into the formulae,

F = (0.6 × 2.5 × 0.8)sin30°

F= 0.6N

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