3. a.50kg rock is tied on a 1.0m string which has a breaking force of 990n. if the string breaks,
what is the speed of the rock?

The velocity of the stone is , v = 4.45 m/s

Explanation:

Given data,

The mass of the rock, m 50 kg

The length of the string, r = 1.0 m

The breaking force of the string, F = 990 N

If the rotated in a circular motion with the string, the string breaks when the centripetal force exceeds 990 N.

The centripetal force is given by the formula,

                                        F = mv²/ r

∴                                        v = √(Fr/m)

                                             = √(990 x 1 / 50)

                                             = 4.45 m/s

Hence, the velocity of the stone is , v = 4.45 m/s

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