Auniform stick 1.0 m long with a total mass of 270 g is pivoted at its center. a 3.0 g bullet is shot through the stick midway between the pivot and one end. the bullet approaches at 250 m/s and leaves at 140 m/s. with what angular speed is the stick spinning after the collision

3.67 rad/s

Explanation:

L = Length of meter stick = 1 m

r = Distance at which the bullet will hit the stick =

m = Mass of bullet = 3 g

M = Mass of stick = 270 g

= Velocity of bullet = 250 m/s

= Velocity of bullet leaving = 140 m/s

Initial angular momentum

Final angular momentum of the system

Since, angular momentum is conserved we have

The angular speed is the stick spinning after the collision is 3.67 rad/s

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