Adamped pendulum has a period of 0.66 s and a time constant of 4.1 s. how many oscillations will this pendulum make before its amplitude has decreased to 20% of its initial amplitude? n=

2.44 oscillation

Explanation:

Damped oscillation equation

Xmax = Aexp(-t/Tc)

Tc=4.1

T=0.66

Xmax= 20% of A = 1/5A

suBstituting into the equation

1/5A= Aexp(-0.66/4.1)

1/5=exp(-0.66/4.1)

In1/5= 1.609

As the period is 0.66, the number of osscillation to gain such amplide is 1.609/0.66

which is 2.44

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s