Suppose the earth's magnetic field at the equator has magnitude 0.50×10−4t and a northerly direction at all points. part a estimate the speed a singly ionized uranium ion (m=238u, we) would need to circle the earth 5.0 km above the equator. express your answer using two significant figures. vv = nothing m/s

v = 1.3 10⁸  m / s

Explanation:

The magnetic force is given by

       F = q v x B

Where blacks indicate vectors

The magnetic field has a direction to the north, the fixed uranium atom on Earth has a direction to the east, so the field and velocity are perpendicular, the expression of the force remains

         F = q v B

If we use Newton's second law

       F = ma

The acceleration is centripetal

      F = m v² / r

The distance is the radius of the earth plus the distance from the surface

      r = Re + 50.103

      r = 6.37 10⁶ + 5 10³

      r = 6.3705 10⁶ m

      m v² / r = q v B

      v = q/m   B r

uranium mass

     m = 238 (1.66 10⁻²⁷) kg = 395 10⁻²⁷ kg

Let's calculate

      v = 1.6 10⁻¹⁹ 0.5 10⁻⁴ 6.3705 10⁶ /395 10⁻²⁷

      v = 1.29 10⁸  m / s

this one:

as we gain mass the force of gravity on us increases.

pls mark me as the ! : d

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles