A3.2 kg particle starts from rest at x = 0 and moves under the influence of a single force fx = 4 + 15.7 x − 1.5 x 2 , where fx is in newtons and x is in meters. find the work done by this force on the particle as the particle moves from x = 0 m to x = 1.3 m. answer in units of j.

Explanation:

Work: This can be defined as the product of force and distance. The unit of work is Joules (J). it can be expressed mathematically as

W = F×d

or

W = .................................. Equation 1

Where b = upper limit, a = lower limit, Fx = expression of force.

Given: a = 0 , b = 1.3 m, Fx = 4 + 15.7x - 1.5x²

Substituting these values into equation 1

W =

W = ᵇ[4x + 15.7x²/2-1.5x³/3 +C]ₐ

Work = upper limit - lower limit

Work = ᵃ[4x + 15.7x²/2 - 1.5x³/3 +C] - [4x + 15.7x²/2 + 1.5x³/3 +C]ᵇ............... Equation 2

Substituting the values of a and b into equation 2

Work = [4(1.3) + 15.7(1.3)²/2-1.5(1.3)³/3 + C] - [0 +C]

Work = [5.2 + 26.53 -3.29 + C] - C

Work = 28.44 J

Work done by the force = 28.44 J.

area of focus

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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