Force of 2000n acts on mass of 0.04kg over a distance of 10m. assuming that mass is initially at rest, find the final velocity and time for which the force acts on the body

Data:- F=2000N m=0.04kg s=10m vi=o(mass is initially at rest) to find vf=? and t=?

Explanation:

solution :- F=ma to find acceleration a=f/m ,a=2000/0.04=50000 a=50000m/sec² now find time according second eq of motion s=vit+1/2at², 10=0×t +1/2 50000 ×t² ,10=25000×t² ,t²=10÷25000=0.0004 sq root on bothside

t=0.02sec now find vf so according to first eq of motion vf=vi+at , vf=0+50000×0.02=1000m/sec acceleration=50000m/sec²,t=0.02sec and vf=1000m/s.

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is