Suppose a disk is 0.50 cm thick and 4.0 cm in diameter. if this disk supports half the weight of a 95 kg person, by what fraction of its thickness does the disk compress?

37.04 %

Explanation:

Young modulus of the disk = stress / strain = F t/ AΔt

where t = thickness in meters = 0.5 cm = 0.5 / 100 = 0.005 m

Δt = the change in the thickness of the disk in meters

F = 95 × 9.8 ( mass × acceleration due to gravity) = 931 N

half of the weight of the man = 931 / 2 = 465.5

young modulus of the disk = 1.0 × 10⁶ N/m²

radius = diameter / 2 = 4 /2 = 2 cm = 2/100 = 0.02 m

Area of the disk = πr² = 3.142 × ( 0.02)²= 0.0012568 m²

1.0 × 10⁶ N/m²  = (  465.5 × 0.005) / ( 0.0012568 × Δt)

0.0012568 Δt = 465.5 × 0.005) / (1.0 × 10⁶) = 2.3275 × 10⁻⁶

Δt = 2.3275 × 10⁻⁶ / 0.0012568 = 0.001852 m

the fraction the disk was compress = 0.001852 / 0.005 × 100 = 37.04 %

terd muffin is the correct answer

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!