Physics, 22.01.2020 05:31 angemango3423

1. a ball is thrown straight up into the air with an initial speed of 8.0 m/s.
a. how long does it take for the rocket to reach its highest point?
b. what is the maximum height the ball reaches above the ground?

Answers: 2

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Answers

Answer from: quissowavyquis8484

The Time taken to reach the highest point is t = 0.816 s.The maximum height of the ball is 3.26 m.

Explanation:

When an object falls freely, it falls due to the influence of gravity and this free falling object is called as acceleration of gravity. The free falling object has an acceleration value of about 9.8 m / s^2 downward on Earth.

The Acceleration of Gravity is denoted by a symbol g.

Solution:

Initial speed = 8.0 m / s.

a. To calculate the time taken, (initial velocity is 8.0 m/s and the final velocity is 0)

T = Velocity / gravity

Time taken to reach highest point t = 8 / 9.8 = 0.816 s.

b. To calculate the height, (initial velocity is 8.0 m/s and the final velocity is 0)

h = square of velocity / (2 * g)

The maximum height the ball reaches h = (8 * 8) / (2 * 9.8)

= 64 / 19.6 = 3.26 m.

Answer from: Quest

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.

brainliest if you have proof from k12 test and provide evidence wit image! provide image evi

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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1. a ball is thrown straight up into the air with an initial speed of 8.0 m/s.
a. how long does...

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