If three of 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28-volt circuit, how much current will flow through the 3-ohm resistor? a - 9.3 amperesb - 1.05 amperesc - 0.93 amperes

Explanation:

We know that in series connection current in all the resistors are same.

Effective resistance is sum of individual resistances.

Here three of 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28-volt circuit

Effective resistance = 3 + 5 + 22 = 30 ohms

Voltage = 28 V

We know

        Voltage = Current x Resistance

         V = IR

         28 = 30 x I

         I = 0.93 A

Current in each resistor is 0.93 A

Option C is the correct answer.

3.2x10^7