Acarnot heat engine receives 3,200 kj/s of heat from a high temperature source at 825 ℃ and rejects heat to a cold temperature sink at 15 ℃. solve following questions:

a. what is the thermal efficiency of this engine?
b. what is the power delivered by the engine in watts?
c. at what rate is heat rejected to the cold temperature sink?
d. what is the entropy change of the sink?

Explanation:

Given:

source temperature T1= 825° C = 1099 K

Sink temperature T2= 15°C = 288 K

Heat Supplied to the engine Qs= 3200 KW

a) Efficiency of a Carnot engine is

=0.7379

=73.79%

b)

let W be the powe delivered

W= 2361.408 KW

c) Heat rejected to the cold temperature Qr= Qs-W

= 3200-2361.408=838.60 KW

d) Entropy change in the sink

=838.60/288= 2.911 W/K

a.

b.

c.

d.

Explanation:

Given:

a.

Since the engine is a Carnot engine:

b.

Now the power delivered:

since here we are given with the rate of heat transfer

c.

rate of heat rejection to the sink:

d.

before we can answer, we have to see the choices that are printed there with the question.   that's the only way we can point you to the correct one.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.