Asmall object is attached to a horizontal spring and set in simple harmonic motion with amplitude a and period t. how long does it take for the object to travel a total distance of 6a? t/2

1.5T

Explanation:

Since, the amplitude of SHM is A. So, in one time period T the object will travel travel a distance of 4A.

6A-4A= 2A.

Now, this 2A distance must be traveled in T/2 time period.

So, the total time taken to travel a distance of 6A is T+T/2 = 3T/2 = 1.5T

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