The velocity of an 11-kg box changes from 5.1 m/s to 15 m/s. How much
total work is done on the box?
O A. 1,100 3
OB. 1,500 3
OC. 2,100 J
OD. 2,500

The total work done on the box will be equal to 1100 J.

Option A

Explanation:

As per work energy theorem, total work done on any object will be equal to the change in kinetic energy of the object.

So change in kinetic energy =

Here, m is the mass, v is the final velocity and u is the initial velocity of the object.

As the mass is given as 11 kg and the final velocity is given as 15 m/s with the initial velocity of the box being 5.1 m/s, then the change in kinetic energy will be as follows.

Kinetic energy = (0.5×11)×()=0.5×11×198.99

Thus, the kinetic energy = 1094 J.

According to the options, this value is nearly equal to 1100 J. Thus, the total work done on the box will be equal to 1100 J.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

it is a negative acceleration