A particle moves around a semicircle of radius R, from one end A of a diameter to the other B. It is attracted to its starting point A by a force proportional to its distance from A. When the particle is at B, the force towards A is F0. Calculate the work done against this force when the particle moves around the semicircle from A to B.

Explanation:

As the particle moves along the circumference of semicircle . It reaches from A to B . The force at B is F₀.  The displacement from A to B is 2 R .

Because the displacement is defined as the shortest path between two points . Here it is 2 R .

The work done can be defined as the product of force and displacement .

Thus the work done in moving from A to B  =  F₀ x 2 R  = 2 F₀ R

answer: (431,2)

step-by-step explanation:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.