A man pushes a cart with force of 120-N at an angle of 50 degrees with the ground. If he walks a horizontal displacement of 20-m going to cashier who's much work is done!

The answer to your question is     Work = 1542.7 J

Explanation:

Data

Force = 120N

angle = 50°

distance = 20 m

Work = ?

Process

1.- Find the horizontal component of the force

           cos Ф = adjacent side / hypotenuse

Solve for adjacent side

            Adjacent side = hypotenuse x cosФ

            Adjacent side = 120 x cos 50

            Adjacent side = 77.13 N

2.- Find the Work

Formula

  Work = Force x distance

Substitution

   Work = 77.13 x 20

Simplification and result

    Work = 1542.7 J

0.19 m/s and 0.45 m/s