A 0.300-kg particle has a speed of 1.00 m/s at point circled A and kinetic energy of 7.60 J at point circled B.

(a) What is its kinetic energy at circled A? J

(b) What is its speed at circled B? m/s

(c) What is the net work done on the particle by external forces as it moves from circled A to circled B? J

Mass of particle , m = 0.3 kg .

Speed of object at position A ,

Kinetic energy of object at position B ,

Now,

A) Kinetic energy of object at position A ,

B) We know,

Putting all values in above equation :

We get ,

C) We know by work energy theorem :

Work Done = Change in Kinetic Energy

Hence , this is the required solution .

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Work and Energy

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