A spherical volume of space has an electric field of intensity 130 N/C directed radially outward from it surface of radius 0.4 m. What is the net charge enclosed within this surface? (ε0 = 8.85 × 10–12 F/m)

Therefore,

The net charge enclosed within this surface is

Explanation:

Given:

Radius, r = 0.4 m

Electric field at the sphere's surface

E = 130 N/C

To Find:

Charge, Q = ?

Solution:

Electric field at the sphere's surface is given as,

Where,

E = Electric Field ,

ε0 = permeability free space = 8.85 × 10–12 F/m

Q = Charge

r  =  Radius

Substituting the values we get

Therefore,

The net charge enclosed within this surface is