Determine the rate at which the electric field changes between the round plates of a capacitor, 8.0 cm in diameter, if the plates are spaced 1.5 mm apart and the voltage across them is changing at a rate of 140 V/s .

Explanation:

It is known that the relation between electric field and potential difference between the plates of a parallel plate capacitor is as follows.

           E =

So, differentiating this on both the sides with respect o time as follows.

Hence, rate of electric field changes between the plates of parallel plate capacitor as follows.

                 =

                 = V/ms

Thus, we can conclude that the rate at which the electric field changes between the round plates of a capacitor is V/ms.

b would be the answer

gravity

explanation: