Imagine an astronaut in space at the midpoint between two stars of equal mass. if all other objects are infinitely far away, what is the weight of the astronaut? explain your answer. step by step?

W = 0 kg

Explanation:  In this situation, the only forces acting on the astronaut are the gravitational forces of both stars.

The gravitational force is described by the equation F = G*(Ms*Ma)/r^2

where G is a constant, Ms and Ma are the masses of the star and astronaut, and r is the distance between them.

Because both stars have the same masss and are at the same distance from the astronaut, the gravitational forces that both stars are applying in the astronaut are equal in magnitude. But because both stars are in opposite sides with respect to the astronaut, the forces cancel each other.

So the gravitational acceleration of the astronaut is 0 m/s^2, and as we know the weight of an object is equal to the product between the mass of the object and the gravitational acceleration applied in the object, so the weight of the astronaut is W = Ma*0 = 0 kg

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

1 the 4 is sig