The following model was presented to aid students in comparing and contrasting the Gravitational and Electrostatic Forces. The teacher told the students that there was missing information from the model and asked them to revise the model to make it more correct. What should the students add to the model and why?

Short arrows of equal length are added to the gravitational force model.

While long arrows with the same length are added to the electrostatic model inorder to show the relative strength of each force in it.

The gravitational force arrows are pointed toward each another simply because the force attracts.

Electrostatic force arrows must be pointed toward each other for charges of objects that are opposite, and away for object with like charges this is because objects with the similar charge will repel one another.

Explanation:

the model is from the attachment

Add short arrows of equal length to the gravitational force model and long arrows of equal length to the electrostatic model to show the relative strength of each force. Arrows for gravitational force should point toward one another because the force attracts. Arrows for electrostatic force should be drawn toward each other for oppositely charged objects and away from each other for like charged objects because objects with the same charge will repel one another.

Explanation:

The picture of model missing in question is attached.

prolly a beacuse the momentuem the car has increases while going down hill

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s