Physics, 07.04.2020 00:09 sierravick123owr441

Water enters a house through a pipe 2.40 cm in diameter, at an absolute pressure of 4.10 atm. The pipe leading to the second floor bathroom, 5.20 m above, is 1.20 cm in diameter. The flow speed at the inlet pipe is 4.75 m/s. a) What is the algebraic expression for flow speed in the bathroom? b) Calculate the flow speed in the bathroom. c) What is algebraic expression for the pressure in the bathroom? d) Calculate the water pressure in the bathroom. Report your answer in the (atm) unit.

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Answer from: hinacat87

Explanation:

We shall apply theory volume conservation to calculate rate of flow of water .

a ) A₁ V₁ = A₂V₂ , A₁ and A₂ are area of cross section and V₁ , V₂ are velocity of flow at two places along pipe.

b ) π x 1.2² x 4.75 = π x 0.6² x V₂

V₂ = 4 X 4.75

= 19 m /s

c )

For finding pressure we shall apply Bernoulli's theorem

P₁ + 1 / 2 ρ v₁² = P₂ + 1 /2 ρ v₂² + ( h₂ - h₁ ) ρ g

P₁ and P₂ are pressure at ground and second floor , v₁ and v₂ are velocity at two floors and h₁ , h₂ are height of two floors . ρ is density of water.

4.1 x 10⁵ + 1/2 x 1000 x 4.75² = P₂ + 1/2 x 1000 x 19² + 5.2 x 1000 x 9.8

4.1 x 10⁵ + .11 x 10⁵ = P₂ + 1.8 X 10⁵ + .51 X 10⁵

P₂ = 1.9 X 10⁵

= 1.9 atm .

Answer from: Quest

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

Answer from: Quest

The answer is 4f======since electrostatic force is given by $f_{elec} = \dfrac{kq_1 q_2}{r^2}$ we let f be the electrostatic force when r = 1 m $f = \dfrac{kq_1 q_2}{1^2} = kq_1q_2$ if we let $f_{0.5}$ denote the electrostatic force when the distance is decreased so that r = 0.5m, then $\begin{aligned} f_{0.5} & = \dfrac{kq_1 q_2}{0.5^2} \\ & = \frac{1}{0.5^2} \cdot kq_1q_2 \\ & = \frac{1}{\left( \frac{1}{2}\right)^2} \cdot kq_1q_2 \\ & = 4 \cdot \boxed{ kq_1q_2 } \end{aligned}$ we established earlier that f = kq₁q₂. therefore $f_{0.5} = 4 f$ the force will now be 4f.

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Water enters a house through a pipe 2.40 cm in diameter, at an absolute pressure of 4.10 atm. The pi...

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