A loop circuit has a resistance of R1 and a current of 2.2 A. The current is reduced to 1.6 A when an additional 2.8 Ω resistor is added in series with R1. What is the value of R1? Assume the internal resistance of the source of emf is zero. Answer in units of Ω

Value of is 7.466 ohm

Explanation:

Let emf of the battery is e

In first case when only is there current through battery is 2.2 A

So

......eqn 1

In second case current is reduced to 1.6 A when additional resistance of 2.8 ohm is added in series

So

....eqn 2

Fro eqn 1 and eqn 2

So value of is 7.466 ohm

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