An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of

Complete Question

An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?

The magnetic field strength is  

Explanation:

The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression

      Making v the subject

 Where m is the mass of electron

              v is the velocity of electron

              q charge on electron

                is the potential difference  

Substituting values

         f

For the electron to move in a circular path the magnetic force[] must be equal to the centripetal force[] and this is mathematically represented as

making B the subject

r is the radius with a value = 5.4cm =

Substituting values

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pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y