A tennis ball is struck in such a way that it leaves the racket with a speed of 31.0m/s in the horizontal direction. When the ball hits the court, it is a distance of 13.3m from the racket. Find the height of the racket ball when it left the racket.

Height of the racket ball = 0.86 m

Explanation:

Given:

Speed of the tennis ball,= 31 m/s

Distance covered, = 13.3 m

We have to find the height of the racket ball when it left the racket.

Lets say that the time taken by the ball to hit the court be 't' seconds.

⇒

⇒

⇒

⇒ seconds

Now we have to find the height lets say that the height is 'h' meter.

⇒     ...second equation of motion

⇒          ...initial velocity = 0 and acceleration = gravity

⇒

⇒

⇒ meter.

So the height of the racket ball when it left the racket is of 0.86 m.

lower, it's not as dense as chocolate syrup.

choco syrup is more like a solid than a liquid and even turns solid if it gets slightly cold,

orange juice however is a 95% liquid and has a very low viscosity

more than, less

less than, more