Two long parallel wires are separated by 18 cm. One of the wires carries a current of 8 A and the other carries a current of 26 A. The permeabilty of free space is 1.257 × 10−6 N · m/A. Determine the magnitude of the magnetic force on a 2.1 m length of the wire carrying the greater current.

The magnitude of the magnetic force on the wire carrying greater current is is 4.85 x 10⁻⁴ N

Explanation:

Given;

distance of separation of the two wires, d = 18 cm

current in the first wire, I₁ = 8 A

current in the second wire, I₂ = 26 A

length of the wire, L = 2.1 m

permittivity of free space, μ₀ = 4π x 10⁻⁷ N·m/A = 1.257 × 10⁻⁶ N·m/A

The magnitude of the magnetic force on the wire carrying greater current is given as;

Therefore, the magnitude of the magnetic force on the wire carrying greater current is is 4.85 x 10⁻⁴ N

gas and liquid

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.